Module:Roman Year
Revision as of 21:17, 10 June 2022 by Procurator-Imperii-Romani (talk | contribs) (Created page with "local p = {} local numeral = require("Module:Roman Numeral") local function _main(args) if args[1] == nil then return end local num = tonumber(args[1]) if not num then return end if num > 0 then avc = 753 elseif num < 0 then avc = 754 end return numeral.main({num + avc}) .. ' AVC' end function p.main(frame) -- If called via #invoke, use the args passed into the invoking -- template, or the args passed to #invoke if any ex...")
Documentation for this module may be created at Module:Roman Year/doc
local p = {}
local numeral = require("Module:Roman Numeral")
local function _main(args)
if args[1] == nil then return end
local num = tonumber(args[1])
if not num then return end
if num > 0 then
avc = 753
elseif num < 0 then
avc = 754
end
return numeral.main({num + avc}) .. ' AVC'
end
function p.main(frame)
-- If called via #invoke, use the args passed into the invoking
-- template, or the args passed to #invoke if any exist. Otherwise
-- assume args are being passed directly in from the debug console
-- or from another Lua module.
local origArgs
if frame == mw.getCurrentFrame() then
origArgs = frame:getParent().args
for k, v in pairs(frame.args) do
origArgs = frame.args
break
end
else
origArgs = frame
end
-- Trim whitespace and remove blank arguments.
local args = {}
for k, v in pairs(origArgs) do
if type( v ) == 'string' then
v = mw.text.trim(v)
end
if v ~= '' then
args[k] = v
end
end
-- exit if not given anything
if args == nil or args == {} then return end
-- Given mathematical expression, simplify to a number
if type(args[1]) == 'string' then
args[1] = mw.ext.ParserFunctions.expr(args[1])
end
return _main(args)
end
return p